We’re being asked to recognize theoxidation state that phosphorusinPO43– (phosphate ion).

You are watching: Oxidation number of p in phosphate ion

Therules because that oxidation statesare as follows:

A. General Rules:

1. For an atom in that elemental kind (Zn, Cl2, C(graphite), etc.) O.S. = 0

2. Because that an ion (Li+, Al3+, etc.) O.S. = charge

B. Specific Rules:

1. Group 1A O.S. = +1

2. Team 2A O.S. = +2

3. Hydrogen O.S. = +1, with nonmetals

O.S. = –1 v metals and boron

4. Fluorine O.S. = –1

5. Oxygen O.S. = –1 in peroxides (X2O2, X = group 1A)

O.S. = –1/2 in superoxides (XO2, X = team 1A)

O.S. = –2 in various other compounds

6. Team 7A O.S. = –1 (except when bonded come O)

Since PO43– is neither a peroxide or superoxide,the oxidation state of every oxygen atom is –2.

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Problem Details

What is the oxidation number of phosphorus in PO43−?

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